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NCERT Solutions for Class 9 Maths Chapter 11 Constructions are prepared by CBSE student eCARE expert to score good marks in class 9. This chapter contain many topics which are very important to score good in class 9. There are some important topic/Activity mentioned below:
Construct a right triangle whose base is 12 cm and sum of its hypotenuse and other side is 18 cm.
Solution:
Steps of Construction:
Step I : Draw BC = 12 cm.
Step II : At B, construct ∠CBY = 90°.
Step III : Along BY¯¯¯¯¯¯¯¯, cut off a line segment BX = 18 cm.
Step IV : Join CX.
Step V : Draw PQ, perpendicular bisector of CX, which meets BX at A.
Step VI : Join AC.
Thus, ?ABC is the required triangle.
Question 1.
Construct a ? ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm.
Solution:
Steps of Construction:
Step I : Draw BX¯¯¯¯¯¯¯¯.
Step II : Along BX¯¯¯¯¯¯¯¯, cut off a line segment BC = 7 cm.
Step III : At B, construct ∠CBY = 75°
Step IV : From BY¯¯¯¯¯¯¯¯, cut off BD = 13 cm (= AB + AC)
Step V : Join DC.
Step VI : Draw a perpendicular bisector of CD which meets BD at A.
Step VII: Join AC.
Thus, ?ABC is the required triangle.
Ex 11.2 Class 9 Maths Question 2.
Construct a ABC in which BC = 8 cm, ∠B = 45° and AB – AC = 35 cm.
Solution:
Steps of Construction:
Step I : Draw BX¯¯¯¯¯¯¯¯.
Step II : Along BX¯¯¯¯¯¯¯¯, cut off a line segment BC = 8 cm.
Step III : At B, construct ∠CBY = 45°
Step IV : From BX¯¯¯¯¯¯¯¯, cut off BD = 3.5 cm (= AB – AC)
Step V : Join DC.
Step VI : Draw PQ, perpendicular bisector of DC, which intersects BY¯¯¯¯¯¯¯¯ at A.
Step VII: Join AC.
Thus, ?ABC is the required triangle.